TS EAMCET · Chemistry · Solutions
The weight in grams of a non-volatile solute (mol. wt. 60) to be dissolved in \(90 \mathrm{~g}\) of water to produce a relative lowering of vapour pressure of 0.02 is
- A \(4\)
- B \(8\)
- C \(6\)
- D \(10\)
Answer & Solution
Correct Answer
(C) \(6\)
Step-by-step Solution
Detailed explanation
Relative lowering of vapour pressure, \(\begin{aligned} \frac{p^{\circ}-p_s}{p^{\circ}} & =x_A \\ & =\frac{\frac{w_A}{m_A}}{\frac{w_A}{m_A}+\frac{w_B}{m_B}}\end{aligned}\) (where, \(w_A\) and \(m_A\) are the mass and molar mass of solute and \(w_B\) and \(m_B\) are the mass and…
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