TS EAMCET · Maths · Probability
An urn contains 7 red, 5 white and 3 black balls. Three balls are drawn randomly one after the other without replacement. If it is known that first ball drawn is red and the second ball drawn is white, then the probability that the third ball drawn is not red is
- A \(\frac{10}{13}\)
- B \(\frac{8}{13}\)
- C \(\frac{12}{13}\)
- D \(\frac{7}{13}\)
Answer & Solution
Correct Answer
(D) \(\frac{7}{13}\)
Step-by-step Solution
Detailed explanation
After 1st red and 2nd white balls are drawn, remaining balls: \(6\) red, \(4\) white, \(3\) black. Total remaining balls: \(6+4+3=13\). Number of non-red balls remaining: \(4+3=7\). P(3rd ball not red)…
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