TS EAMCET · Maths · Pair of Lines
The combined equation of the diagonals of the parallelogram formed by the lines \(\left(7 x^2-4 x y+8 y^2\right)^2+(4 x-8 y-32)\) \(\left(7 x^2-4 x y+8 y^2\right)=0\) is
- A \(x^2-x y+y^2+3 x-15 y=0\)
- B \(3 x^2-6 x y-2 y^2-15 x-17 y=0\)
- C \(3 x^2-5 x y-2 y^2-24 x-8 y=0\)
- D None of these
Answer & Solution
Correct Answer
(D) None of these
Step-by-step Solution
Detailed explanation
\(\left(7 x^2-4 x y+8 y^2\right)^2+(4 x-8 y-32)\) \(\left(7 x^2-4 x y+8 y^2\right)=0\) \(\Rightarrow\left(7 x^2-4 x y+8 y^2\right)\left(7 x^2-4 x y+8 y^2+4 x-8 y-32\right)=0\) Now, \(7 x^2-4 x y+8 y^2+4 x-8 y-32=0\) \(\Rightarrow \quad 7 x^2+(-4 y+4) x+8 y^2-8 y-32=0\) Which is…
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