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TS EAMCET · Maths · Application of Derivatives

The equation of the normal to the curve sin \(y=\sqrt{3} x \sin \left(\frac{\pi}{6}+y\right)\) at \(x=0\), is

  1. A \(2 x+\sqrt{3} y=0\)
  2. B \(2 x+y=0\)
  3. C \(x+2 y=0\)
  4. D \(\sqrt{3} x+2 y=0\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(2 x+\sqrt{3} y=0\)

Step-by-step Solution

Detailed explanation

Given equation of curve is \(\sin y=\sqrt{3} x \sin \left(\frac{\pi}{6}+y\right)\) ...(i) at \(x=0 \Rightarrow \sin y=0\) or \(y=0\) now differentiating eq. (i) w.r.t. \(x\)…