TS EAMCET · Maths · Circle
If \(2 x-3 y+5=0\) and \(4 x-5 y+7=0\) are the equations of the normals drawn to a circle and \((2,5)\) is a point on the given circle, then the radius of the circle is
- A 1
- B 2
- C 3
- D 4
Answer & Solution
Correct Answer
(B) 2
Step-by-step Solution
Detailed explanation
\(2(2x - 3y + 5) - (4x - 5y + 7) = 0\) \(4x - 6y + 10 - 4x + 5y - 7 = 0 \implies -y + 3 = 0 \implies y = 3\) \(2x - 3(3) + 5 = 0 \implies 2x - 9 + 5 = 0 \implies 2x - 4 = 0 \implies x = 2\) Center is \((2,3)\). \(r = \sqrt{(2-2)^2 + (5-3)^2}\)…
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