TS EAMCET · Maths · Complex Number
If \(\frac{2+3 i}{i-2}-\frac{4 i-3}{3+4 i}=x+i y\), then \(3 x+y=\)
- A \(4\)
- B \(-4\)
- C \(-2\)
- D \(2\)
Answer & Solution
Correct Answer
(B) \(-4\)
Step-by-step Solution
Detailed explanation
\( \frac{2+3 i}{i-2} = \frac{(2+3i)(-2-i)}{(-2+i)(-2-i)} = \frac{-4-2i-6i+3}{4+1} = \frac{-1-8i}{5} \) \( \frac{4 i-3}{3+4 i} = \frac{(-3+4i)(3-4i)}{(3+4i)(3-4i)} = \frac{-9+12i+12i+16}{9+16} = \frac{7+24i}{25} \)…
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