TS EAMCET · Maths · Continuity and Differentiability
Let \(f:[-1,2] \rightarrow \mathbb{R}\) be defined by \(f(x)=\left[x^2-3\right]\) where \([\cdot]\) denotes greatest integer function, then the number of points of discontinuity for the function \(f\) in \((-1,2)\) is
- A 5
- B 4
- C 3
- D 2
Answer & Solution
Correct Answer
(B) 4
Step-by-step Solution
Detailed explanation
For \(x \in (-1,2)\), \(x^2 \in [0,4)\), so \(x^2-3 \in [-3,1)\). The function \(f(x)=\left[x^2-3\right]\) is discontinuous when \(x^2-3\) is an integer. \(x^2-3 \in \{-3, -2, -1, 0\}\). \(x^2 \in \{0, 1, 2, 3\}\). \(x = 0\) (for \(x^2=0\)). (\(0 \in (-1,2)\)) \(x = 1\) (for…
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