TS EAMCET · Maths · Circle
The equation of the circle passing through the points of intersection of the circles \(x^2+y^2+6 x+4 y-12=0\), \(x^2+y^2-4 x-6 y-12=0\) and having radius \(\sqrt{13}\) is
- A \(x^2+y^2-2 x-12=0\)
- B \(x^2+y^2-4 x-6 y=0\)
- C \(x^2+y^2-2 y-12=0\)
- D \(x^2+y^2+6 x-4 y=0\)
Answer & Solution
Correct Answer
(C) \(x^2+y^2-2 y-12=0\)
Step-by-step Solution
Detailed explanation
Equation of circle through point of intersection of \(S_1\) and \(S_2\) is…
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