TS EAMCET · Maths · Trigonometric Ratios & Identities
If \(\cos \frac{\pi}{7} \cos \frac{2 \pi}{7} \cos \frac{4 \pi}{7}=\frac{\sin \frac{8 \pi}{7}}{8 \sin \frac{\pi}{7}}\) then, \(\sin \frac{\pi}{14} \sin \frac{3 \pi}{14} \sin \frac{5 \pi}{14} \sin \frac{7 \pi}{14} \sin \frac{9 \pi}{14} \sin \frac{11 \pi}{14} \sin \frac{13 \pi}{14}=\)
- A \(\frac{1}{16}\)
- B \(\frac{1}{32}\)
- C \(\frac{1}{64}\)
- D \(\frac{1}{128}\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{64}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \quad \sin \frac{\pi}{14} \cdot \sin \frac{3 \pi}{14} \cdot \sin \frac{5 \pi}{14} \cdot \sin \frac{7 \pi}{14} \cdot \sin \frac{9 \pi}{14} \cdot \sin \frac{11 \pi}{14} \cdot \sin \frac{13 \pi}{14} \\ & \because \quad \sin \frac{13 \pi}{14}=\sin…
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