TS EAMCET · Maths · Straight Lines
The equation of a line making an angle \(60^{\circ}\) with the line \(x+y-3=0\) and passing through the point \((1,1)\) is
- A \((1+\sqrt{3}) x+(1-\sqrt{3}) y-2=0\)
- B \(2 x+y-3=0\)
- C \(\sqrt{3} x+(1-\sqrt{3}) y=1\)
- D \(\sqrt{3} x+(2+\sqrt{3}) y=2(1+\sqrt{3})\)
Answer & Solution
Correct Answer
(A) \((1+\sqrt{3}) x+(1-\sqrt{3}) y-2=0\)
Step-by-step Solution
Detailed explanation
We know that the equation of two straight lines which passes through a point \(\left(x_1, y_1\right)\) and made a given angle \(\alpha\) with the given straight line \(y=m x+c \text { are } y-y_1=\frac{m \pm \tan \alpha}{1 \mp m \tan \alpha}\left(x-x_1\right)\) Here,…
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