TS EAMCET · Maths · Area Under Curves
The area (in square units) bounded by the curves \(|x|=2,|y|=2\) and \(x y \leq \frac{1}{2}\) is
- A \(9+3 \log 2\)
- B \(3+\log 2\)
- C \(2+\log 3\)
- D \(8+2 \log 3\)
Answer & Solution
Correct Answer
(A) \(9+3 \log 2\)
Step-by-step Solution
Detailed explanation
We have, \(|x|=2,|y|=2, x y \leq \frac{1}{2}\)…
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Maths
- For \(a>0\), if \(f(x)=a x+b\) is an onto function from \([-1,1]\) to \([0,2]\), then \(\cot \left[\tan ^1 \frac{1}{7}+\tan ^1 \frac{1}{8}+\tan ^1 \frac{1}{5}\right]=\)TS EAMCET 2019 Medium
- The vertex of the parabola is at the centre of a circle and the parabola cuts that circle at the ends of its latus rectum. Then the equation of that circle isTS EAMCET 2019 Medium
- If \(6 x-5 y-20=0\) is a normal to the ellipse \(x^2+3 y^2=k\), then \(k=\)TS EAMCET 2024 Easy
- The equation of the plane passing through \((1,1,1)\) and \((1,-1,-1)\) and perpendicular to \(2 x-y+z+5=0\) is :TS EAMCET 2003 Medium
- If \(\cosh \beta=\sec \alpha \cos \theta, \sinh \beta=\operatorname{cosec} \alpha \sin \theta\), then \(\sinh ^2 \beta=\)TS EAMCET 2018 Easy
- One of the roots of the equation \(x^{14}+x^9-x^5-1=0\) isTS EAMCET 2024 Easy
More PYQs from TS EAMCET
- For all integers \(n \geq 1\), which of the following is divisible by 9 ?TS EAMCET 2006 Easy
- 2-pentyne on reaction with sodium in liquid ammonia produced compound \(A\). What is \(A\) ?TS EAMCET 2018 Easy
- If the line \(x-y=-4 K\) is a tangent to the parabola \(y^2=8 x\) at \(P\), then the perpendicular distance of normal at \(P\) from \((K, 2 K)\) isTS EAMCET 2017 Easy
- If all the letters of the word 'HANDLE' are permuted in all possible ways and the words (with or without meaning) thus formed are arranged in dictionary order, then the rank of the word 'HELAND' isTS EAMCET 2025 Medium
- The force ( F in newton) acting on a particle of mass 90 g executing simple harmonic motion is given by \(\mathrm{F}+0.04 \pi^2 y=0\), where \(y\) is displacement of the particle in meter. If the amplitude of the particle is \(\frac{6}{\pi} \mathrm{~m}\), then the maximum velocity of the particle isTS EAMCET 2025 Medium
- If \((8,2)\) is a point on the hyperbola whose length of the transverse axis is 12 and conjugate axis is \(x=0\), then the eccentricity of that hyperbola isTS EAMCET 2020 Easy