TS EAMCET · Maths · Differentiation
The derivative of \(\frac{1-x^2}{1+x^2}\) with respect to \(\frac{2 x}{1+x^2}\) at \(\mathbf{x}=2\) is
- A \(0\)
- B \(\frac {4}{3}\)
- C \(1\)
- D \(-\frac {4}{3}\)
Answer & Solution
Correct Answer
(B) \(\frac {4}{3}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \frac{d}{d x}\left(\frac{1-x^2}{1+x^2}\right)=\frac{\left(1+x^2\right)(-2 x)-\left(1-x^2\right)(2 x)}{\left(1+x^2\right)^2} \\ & =\frac{-2 x\left(1+x^2+1-x^2\right)}{\left(1+x^2\right)^2}=\frac{-4 x}{\left(1+x^2\right)^2} \\ & \frac{d}{d x}\left(\frac{2…
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