TS EAMCET · Maths · Binomial Theorem
The coefficient of \(x y^2 z^3\) in the expansion of \((x-2 y+3 z)^6\) is
- A \(6480\)
- B \(3240\)
- C \(1620\)
- D \(810\)
Answer & Solution
Correct Answer
(A) \(6480\)
Step-by-step Solution
Detailed explanation
General term \(=\frac{6!}{a!b!c!} x^a(-2 y)^b \cdot(3 z)^c\) For \(x y^2 z^3 ; a=1, b=2, c=3\) Coefficient of \(x y^2 z^3=\frac{6!}{1!\times 2!\times 3!} \times(-2)^2 \times 3^3=6480\)
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