TS EAMCET · Physics · Electrostatics
A non-conducting solid sphere has radius \(R\) and uniform charge density. A spherical cavity of radius \(\frac{R}{4}\) is hollowed out of the sphere. The distance between center of sphere and center of cavity is \(\frac{R}{2}\). If the charge of the sphere is \(Q\) after the creation of the cavity and the magnitude of electric field at the center of the cavity is \(E=K\left(\frac{Q}{4 \pi \in_0 R^2}\right)\), determined the approximate value of \(K\).
- A 0.32
- B 0.78
- C 0.51
- D 0.45
Answer & Solution
Correct Answer
(C) 0.51
Step-by-step Solution
Detailed explanation
A cavity of radius \(\frac{R}{4}\) is made inside a non-conducting solid sphere as shown in the figure. Let \(Q_0\) be the charge, present on the sphere when cavity was absent. Hence, \(E=E_{Q_0}-E_{\text {cavity }}\) Where, \(E=\) electric field at centre of cavity,…
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