TS EAMCET · Maths · Vector Algebra
Let \(\vec{a}=2 \hat{i}-\hat{j}+\hat{k}\) be the position vector of a point \(\mathrm{A}\). Let \(\vec{b}=\hat{i}+2 \hat{j}-\hat{k}\) and \(\vec{c}=\hat{i}+\hat{j}-2 \hat{k}\) be two vectors and \(\vec{r}\) be a vector passing through the point \(A(\vec{a})\) and parallel to the vector \(\vec{b}\). If the projection of \(\vec{r}\) on \(\vec{c}\) is \(\frac{9}{\sqrt{6}}\) then \(|\vec{r}|=\)
- A \(\sqrt{26}\)
- B 5
- C \(\sqrt{5}\)
- D \(\sqrt{34}\)
Answer & Solution
Correct Answer
(A) \(\sqrt{26}\)
Step-by-step Solution
Detailed explanation
Equation of vector passing through \(\vec{a}\) and parallel to \(\vec{b}\) is \(\vec{r}=\vec{a}+\lambda \vec{b}\) \(\vec{r}=(2 \hat{i}-\hat{j}+\hat{k})+\lambda(\hat{i}+2 \hat{j}-\hat{k})\) \(=(2+\lambda) \hat{i}+(2 \lambda-1) \hat{j}+(1-\lambda) \hat{k}\) Projection of…
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