TS EAMCET · Maths · Circle
The circle \(x=5 \cos \theta, y=5 \sin \theta\) is bounded by the rectangle formed by the lines \(x \pm 6=0\) and \(y \pm 6=0\). The area of the triangle that lies inside the rectangle which is formed by the tangent at \(P\left(\frac{2 \pi}{3}\right)\) to the circle with two of the above given lines is
- A \(\frac{62-24 \sqrt{3}}{\sqrt{3}}\)
- B \(\frac{1}{2}(6 \sqrt{3}-4)^2\)
- C \(48+\sqrt{3}\)
- D \(\frac{1}{2}\left(\frac{6 \sqrt{3}-4}{\sqrt{3}}\right)^2\)
Answer & Solution
Correct Answer
(A) \(\frac{62-24 \sqrt{3}}{\sqrt{3}}\)
Step-by-step Solution
Detailed explanation
Coordinate of \(P\) will be \(\left(5 \cos \frac{2 \pi}{3}, 5 \sin \frac{2 \pi}{3}\right)\)…
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