ExamBro
ExamBro
TS EAMCET · Chemistry · Solutions

The Henry's law constant for the solubility of \(\mathrm{N}_2\) gas in water at \(298 \mathrm{~K}\) is \(1 \times 10^{+5} \mathrm{~atm}\). The mole fraction of air is 0.8 . The number of moles of \(\mathrm{N}_2\) from air dissolved in 10 moles of water at \(298 \mathrm{~K}\) and 5 atm pressure is

  1. A \(4 \times 10^{-5}\)
  2. B \(4 \times 10^{-4}\)
  3. C \(5 \times 10^{-4}\)
  4. D \(4 \times 10^{-6}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(4 \times 10^{-4}\)

Step-by-step Solution

Detailed explanation

At total pressure \(5 \mathrm{~atm}\), the partial pressure of \(\mathrm{N}_2=5 \times 0.8=4 \mathrm{~atm}\) According to Henry's Law, \[ \mathrm{P}_{\mathrm{N}_2}=\mathrm{K}_{\mathrm{H}} \mathrm{x}_{\mathrm{N}_2} \] \(\left(\mathrm{x}_{\mathrm{N}_2}\right)\) is the mole…