TS EAMCET · Maths · Indefinite Integration
- A
- B
- C
- D
Answer & Solution
Correct Answer
(C)
Step-by-step Solution
Detailed explanation
∫tan−1xx3dx =tan−1x⋅−12x2+12∫1(1+x2)x2dx =−12x2tan−1x+12∫(1x2−11+x2)dx =−12x2tan−1x+12(−1x−tan−1x) =−12x−(12+12x2)tan−1x
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