TS EAMCET · Maths · Properties of Triangles
The angle \(A\) of \(\triangle A B C\) is found by measurement to be \(67 \frac{1^{\circ}}{2}\) and the area of \(\triangle A B C\) is calculated from the measurements of \(b, c, A\). In measuring \(A\), an error of \(9 \mathrm{~min}\) is made then the percentage error in the area of the triangle is
- A \(\frac{\pi}{6}(2-\sqrt{3})\)
- B \(\frac{\pi}{6}(2+\sqrt{3})\)
- C \(\frac{\pi}{12}(\sqrt{2}+1)\)
- D \(\frac{\pi}{12}(\sqrt{2}-1)\)
Answer & Solution
Correct Answer
(D) \(\frac{\pi}{12}(\sqrt{2}-1)\)
Step-by-step Solution
Detailed explanation
Given, \(d \theta=9 {~min}\) In radian \(d \theta=\frac{9}{60} \times \frac{\pi}{180}=\frac{\pi}{1200}\)…
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