TS EAMCET · Maths · Quadratic Equation
\(\alpha, \beta, \gamma, 2, \varepsilon\) are the roots of the equation \(x^5+4 x^4-13 x^3-52 x^2+36 x+144=0 .\) If \(\alpha \lt \beta \lt \gamma \lt 2 \lt \varepsilon\), then \(\alpha+2 \beta+3 \gamma+5 \varepsilon=\)
- A -1
- B 25
- C -36
- D 48
Answer & Solution
Correct Answer
(A) -1
Step-by-step Solution
Detailed explanation
Given that \(\alpha, \beta, \gamma, 2\) and \(\varepsilon\) are roots of the equation \(x^5+4 x^4-13 x^3-52 x^2+36 x+144=0\) Put \(x=-2\) \(-32+64+104-208-72+144=0\) So, \(x=-2\) is also roots Put \(x=3\) \(243+324-351-468+108+144=0\) So, \(x=3\) is also roots…
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