TS EAMCET · Maths · Probability
When a pair of six faced fair dice are thrown, the probability that the sum of the numbers on the two dice is greater than 7 , is
- A \(\frac{1}{3}\)
- B \(\frac{5}{12}\)
- C \(\frac{1}{2}\)
- D \(\frac{1}{4}\)
Answer & Solution
Correct Answer
(B) \(\frac{5}{12}\)
Step-by-step Solution
Detailed explanation
\[ \begin{aligned} \text { Total outcomes } & =36 \\ \text { Favorable outcomes } & =(\text { sum greater than } 7)=15 \\ \therefore \quad \text { Required probability } & =\frac{15}{36}=\frac{5}{12} \end{aligned} \]
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