TS EAMCET · Maths · Probability
If three unbiased dice are rolled simultaneously then the probability that all the three dice show distinct numbers is
- A \(\frac{1}{36}\)
- B \(\frac{35}{36}\)
- C \(\frac{5}{9}\)
- D \(\frac{4}{9}\)
Answer & Solution
Correct Answer
(C) \(\frac{5}{9}\)
Step-by-step Solution
Detailed explanation
Total number of elements in sample space \[ =6 \times 6 \times 6=216 \] Ways to get different numbers on all 3 dice \[ =6 \times 5 \times 4=120 \] \(\therefore \quad\) Probability \(=\frac{120}{216}=\frac{5}{9}\).
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