TS EAMCET · Maths · Determinants
Consider the simultaneous linear equations \(\beta x+\alpha y-z=-1\), \(3 x-\beta y+\alpha z=0 \alpha x+\beta y+z=1\). In the usual notation used in Crammer's rule, given that
\(\frac{\Delta_1}{\Delta}=-1, \frac{\Delta_2}{\Delta}=1 \cdot \frac{\Delta_3}{\Delta}=2\), then \((\alpha, \beta)=\)
- A \((1,2)\)
- B \((2,1)\)
- C \((-1,2)\)
- D \((1,-2)\)
Answer & Solution
Correct Answer
(B) \((2,1)\)
Step-by-step Solution
Detailed explanation
Here we are given that \[ \mathrm{x}=\frac{\Delta_1}{\Delta}=-1, \quad \mathrm{y}=\frac{\Delta_2}{\Delta}=1, \quad \mathrm{z}=\frac{\Delta_3}{\Delta}=2 \] From system of linear eqns.…
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