TS EAMCET · Maths · Limits
- A
- B
- C
- D
Answer & Solution
Correct Answer
(C)
Step-by-step Solution
Detailed explanation
Let, y=limn→∞P1+r100ntn Let, n=1x so when n→∞ then x→0. ∴y= limx→0P1+rx100tx Taking log on both sides, we get lny= limx→0 lnP1+rx100tx ⇒lny= limx→0 lnP+txln1+rx100…
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Maths
- \(f(x)=x^2-2(4 \mathrm{~K}-1) x+g(\mathrm{~K})>0 \forall x \in \mathbb{R}\) and for \(\mathrm{K} \in(\mathrm{a}, \mathrm{b})\). If \(g(\mathrm{~K})=15 \mathrm{~K}^2-2 \mathrm{~K}-7\), thenTS EAMCET 2025 Medium
- If and thenTS EAMCET 2021 Easy
- The tangent at \(A(-1,2)\) on the circle \(x^2+y^2-4 x-8 y+7=0\) touches the circle \(x^2+y^2+4 x+6 y=0\) at \(B\). Then, a point of trisection of \(A B\) isTS EAMCET 2018 Medium
- If \(f\) is defined on \(\mathbb{R}\) such that \(f(\mathrm{x}) f(-\mathrm{x})=9\), then \(\int_{-23}^{23} \frac{d x}{3+f(x)}\)TS EAMCET 2023 Hard
- A normal chord PQ drawn at a point P on the parabola \(y^2=5 x\) subtends a right angle at the vertex. If P lies in the first quadrant, then the other end Q of the normal chord isTS EAMCET 2025 Medium
- \(\frac{1+\tanh \frac{x}{2}}{1-\tanh \frac{x}{2}}\) is equal toTS EAMCET 2008 Medium
More PYQs from TS EAMCET
- If the equilibrium constant for the reaction \(2 A B \rightleftharpoons A_2+B_2\) is 49 , what is the equilibrium constant for \(A B \rightleftharpoons \frac{1}{2} A_2+\frac{1}{2} B_2 ?\)TS EAMCET 2011 Easy
- Match the following

The correct answer isTS EAMCET 2023 Easy - \(\cot \theta-\tan \theta-2 \tan 2 \theta-4 \tan 4 \theta=\)TS EAMCET 2018 Medium
- The specific heat of helium at constant volume is \(12.6 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\). The specific heat of helium at constant pressure in \(\mathrm{J} \mathrm{mol}^{-1} \mathrm{~K}^{-1}\) is approximately (assume, the universal gas constant, \(R=8.314 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\) )TS EAMCET 2020 Easy
- The point on the line \(3 x+4 y=5\) which is equidistant from \((1,2)\) and \((3,4)\) isTS EAMCET 2009 Medium
- If the function \(f: R \rightarrow R\), defined by \(f(x)=\left\{\begin{array}{l}5-3 x, \text { if } x \leq \frac{5}{3} \ x^2-3 x+20, \text { if } x>\frac{5}{3}\end{array}\right.\), then ' \(f\) ' isTS EAMCET 2019 Easy