TS EAMCET · Maths · Application of Derivatives
Suppose \(A, B, C\) and \(D\) are the four intersection points of the curves \(\frac{x^2}{18}+\frac{y^2}{8}=1\) and \(x^2-y^2=5\) in I, II, III and IV quadrants respectively. If \(\theta_1, \theta_2, \theta_3\) and \(\theta_4\) respectively are the angles between the curves at \(A, B, C\) and \(D\), then
- A \(\theta_1 \neq \theta_2 \neq \theta_3 \neq \theta_4\)
- B \(\theta_1=\theta_2, \theta_3=\theta_4, \theta_2 \neq \theta_3\)
- C \(\theta_1=\theta_3, \theta_2=\theta_4, \theta_3 \neq \theta_2\)
- D \(\theta_1=\theta_2=\theta_3=\theta_4\)
Answer & Solution
Correct Answer
(D) \(\theta_1=\theta_2=\theta_3=\theta_4\)
Step-by-step Solution
Detailed explanation
(d) \(\frac{x^2}{18}+\frac{y^2}{8}=1\) ...(i) and \(x^2-y^2=5\) ...(ii)…
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