TS EAMCET · Maths · Binomial Theorem
If \(\mathrm{k}\) is the coefficient of \(x^5\) in the expansion of \(\left(2 x^2-\frac{1}{3 x^3}\right)^5\) then \(\frac{3 \mathrm{k}}{2}=\)
- A -20
- B -40
- C 20
- D 40
Answer & Solution
Correct Answer
(B) -40
Step-by-step Solution
Detailed explanation
Given expression \(\left(2 x^2-\frac{1}{3 x^3}\right)^5\). General term \(\mathrm{T}_{r+1}={ }^5 \mathrm{C}_r\left(2 x^2\right)^{5-r}\left(\frac{-1}{3 x^3}\right)^r\) \(\mathrm{T}_{r+1}={ }^5 \mathrm{C}_r(2)^{5-r}\left(\frac{-1}{3}\right)^r x^{10-2 r-3 r}\) Here, \(10-2 r-3 r\)…
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