TS EAMCET · Maths · Trigonometric Equations
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Answer & Solution
Correct Answer
(A)
Step-by-step Solution
Detailed explanation
We know sinhx=ex-e-x2 & coshx=ex+e-x2. So, sinh[log(2+5)]+cosh[log(2+3)]=elog2+5-e-log2+52+elog2+3+e-log2+32 ⇒sinhlog2+5+coshlog2+3=(2+5)-1(2+5)2+(2+3)+1(2+3)2 ⇒sinh[log2+5]+cosh[log2+3]=4.
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