TS EAMCET · Maths · Complex Number
If \(\mathrm{z}=\mathrm{x}+\mathrm{iy}\) and the point \(\mathrm{P}\) in the Argand plane represents \(z\), then the locus of \(z\) satisfying the equation \(|z-2|+|z-2 i|\) \(=4\) is
- A \(4 x^2+3 x y+4 y^2-6 x-6 y+8=0\)
- B \(3 x^2+2 x y+3 y^2-8 x-8 y+6=0\)
- C \(3 x^2+2 x y+3 y^2-8 x-8 y=0\)
- D \(4 x^2+3 x y+4 y^2-6 x-6 y=0\)
Answer & Solution
Correct Answer
(C) \(3 x^2+2 x y+3 y^2-8 x-8 y=0\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text z=x+i y \\ & |z-2|+|z-2 i|=4 \\ & |(x-2)+i y|+|x+(y-2) i|=4 \\ & \Rightarrow \quad \sqrt{(x-2)^2+y^2}+\sqrt{x^2+(y-2)^2}=4 \\ & \Rightarrow \quad(x-2)^2+y^2=\left[4-\sqrt{x^2+(y-2)^2}\right]^2 \\ & \Rightarrow x^2+y^2-4 x+4 \\ & \quad=16+x^2+y^2+4-4 y-8…
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