TS EAMCET · Maths · Probability
A fair coin is tossed a fixed number of times. If the probability of getting five heads is cqual to that of getting seven heads, then the probability of getting four heads is
- A \(\frac{495}{4096}\)
- B \(\frac{429}{2048}\)
- C \(\frac{165}{1024}\)
- D \(\frac{35}{512}\)
Answer & Solution
Correct Answer
(A) \(\frac{495}{4096}\)
Step-by-step Solution
Detailed explanation
According to Binomial probability distribution, Let ' \(n\) ' number of times coin is tossed. So, probability of getting five heads \(={ }^n C_5\left(\frac{1}{2}\right)^{n-5}\left(\frac{1}{2}\right)^5={ }^n C_5\left(\frac{1}{2}\right)^n\) And probability of getting seven heads…
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