TS EAMCET · Maths · Properties of Triangles
In a \(\triangle A B C\) \[ \frac{(a+b+c)(b+c-a)(c+a-b)(a+b-c)}{4 b^2 c^2} \] equals
- A \(\cos ^2 A\)
- B \(\cos ^2 B\)
- C \(\sin ^2 A\)
- D \(\sin ^2 B\)
Answer & Solution
Correct Answer
(C) \(\sin ^2 A\)
Step-by-step Solution
Detailed explanation
We know that, \(2 s=a+b+c\)…
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