TS EAMCET · Maths · Vector Algebra
If the position vectors of \(A, B\) and \(C\) are respectively \(2 \hat{\mathbf{i}}-\hat{\mathbf{j}}+\hat{\mathbf{k}}, \hat{\mathbf{i}}-3 \hat{\mathbf{j}}-5 \hat{\mathbf{k}}\) and \(3 \hat{\mathbf{i}}-4 \hat{\mathbf{j}}-4 \hat{\mathbf{k}}\), then \(\cos ^2 A\) is equal to
- A \(0\)
- B \(\frac{6}{41}\)
- C \(\frac{35}{41}\)
- D \(1\)
Answer & Solution
Correct Answer
(C) \(\frac{35}{41}\)
Step-by-step Solution
Detailed explanation
Let \(\overrightarrow{O A}=2 \hat{\mathbf{i}}-\hat{\mathbf{j}}+\hat{\mathbf{k}}, \overrightarrow{O B}=\hat{\mathbf{i}}-3 \hat{\mathbf{j}}-5 \hat{\mathbf{k}}\) and…
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