TS EAMCET · Maths · Three Dimensional Geometry
If \((2,-1,3)\) is the foot of the perpendicular drawn from the origin to a plane, then the equation of that plane is
- A \(2 x+y-3 z+6=0\)
- B \(2 x-y+3 z-14=0\)
- C \(2 x-y+3 z-13=0\)
- D \(2 x+y+3 z-10=0\)
Answer & Solution
Correct Answer
(B) \(2 x-y+3 z-14=0\)
Step-by-step Solution
Detailed explanation
Let equation of plane be \( a x+b y+c z+d=0 \) Where \(a, b, c\) are direction ratios of line perpendicular to plane \( \begin{aligned} & a=2-0=2, \\ & b=-1-0=-1 \\ & c=3-0=3 \\ & \therefore 2 x-y+3 z+{d}=0 \end{aligned} \) \(\because\) It passes through \((2,-1,3)\)…
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