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TS EAMCET · Maths · Indefinite Integration

\(\int\left(\frac{\left(\sin ^4 x+2 \cos ^2 x-1\right) \cos x}{(1+\sin x)^6}\right) d x=\)

  1. A \(\frac{\sin ^6 x}{6(1+\sin x)^6}+c\)
  2. B \(-\frac{\sin ^6 x}{6(1+\sin x)^6}+c\)
  3. C \(\frac{\cos ^6 x}{6(1+\sin x)^6}+c\)
  4. D \(-\frac{\cos ^6 x}{6(1+\sin x)^6}+c\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(-\frac{\cos ^6 x}{6(1+\sin x)^6}+c\)

Step-by-step Solution

Detailed explanation

\begin{aligned} & \text { } I=\int \frac{\left(\sin ^4 x+2 \cos ^2 x-1\right)}{(1+\sin x)^6} \cos x d x \\ & =\int \frac{\left(\sin ^4 x-2 \sin ^2 x+1\right)}{(1+\sin x)^6} \cos x d x \\ & =\int \frac{\left(1-\sin ^2 x\right)^2}{(1+\sin x)^6} \cos x d x=\int \frac{(1-\sin…