TS EAMCET · Maths · Straight Lines
The image of the point \((3,8)\) in the line \(x+3 y=7\) is
- A (1, 4)
- B (4, 1)
- C (-1,-4)
- D (-4,-1)
Answer & Solution
Correct Answer
(C) (-1,-4)
Step-by-step Solution
Detailed explanation
The equation of perpendicular line on \(x+3 y=7\) is \(3 x-y+\lambda=0\). Since, it is passes through \((3,8)\). \(\begin{aligned} & \therefore \quad 9-8+\lambda=0 \\ & \Rightarrow \quad \lambda=-1 \\ & \therefore \quad 3 x-y-1=0 \\ & \end{aligned}\) The point of intersection of…
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