TS EAMCET · Maths · Probability
Astudent has to write the words ABILITY, PROBABILITY, FACILITY, MOBILITY. He wrote one word and erased all the letters in it except two consecutive letters. If ' LI ' is left after erasing then the probability that the boy wrote the word PROBABLLITY is
- A \(\frac{21}{116}\)
- B \(\frac{72}{116}\)
- C \(\frac{3}{5}\)
- D \(\frac{2}{3}\)
Answer & Solution
Correct Answer
(A) \(\frac{21}{116}\)
Step-by-step Solution
Detailed explanation
Let \(\mathrm{E}_1, \mathrm{E}_2, \mathrm{E}_3, \mathrm{E}_4\) be the events that boy wrote the words ABILITY, PROBABILITY, FACILITY, MOBILITY respectively. So, \(P\left(E_1\right)=P\left(E_2\right)=P\left(E_3\right)=P\left(E_4\right)=\frac{1}{4}\) A be the event that "LI' left…
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