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TS EAMCET · Maths · Probability

Astudent has to write the words ABILITY, PROBABILITY, FACILITY, MOBILITY. He wrote one word and erased all the letters in it except two consecutive letters. If ' LI ' is left after erasing then the probability that the boy wrote the word PROBABLLITY is

  1. A \(\frac{21}{116}\)
  2. B \(\frac{72}{116}\)
  3. C \(\frac{3}{5}\)
  4. D \(\frac{2}{3}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{21}{116}\)

Step-by-step Solution

Detailed explanation

Let \(\mathrm{E}_1, \mathrm{E}_2, \mathrm{E}_3, \mathrm{E}_4\) be the events that boy wrote the words ABILITY, PROBABILITY, FACILITY, MOBILITY respectively. So, \(P\left(E_1\right)=P\left(E_2\right)=P\left(E_3\right)=P\left(E_4\right)=\frac{1}{4}\) A be the event that "LI' left…
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