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TS EAMCET · Maths · Application of Derivatives

Let fx be continuous on 0,6 and differentiable on 0,6 Let f0=12 and f6=-4. If gx=fxx+1, then for some Lagrange's constant c0,6,g'c=

  1. A -443
  2. B -2221
  3. C 3221
  4. D 4421
Verified Solution

Answer & Solution

Correct Answer

(D) 4421

Step-by-step Solution

Detailed explanation

gx=fxx+1·f0=12, f6=-4 C∈0,6 ⇒ g0=f00+1=121=12 ⇒ g6=f66+1=-47 From Lagrange's theorem, g'c=g6-g06-0 =-47-126=-8842 ∴g'c=-4421
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