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TS EAMCET · Maths · Indefinite Integration

Let fx=2x3-3x2+4x-5x2dx and f1=1. Then f5=

  1. A 10+4log5
  2. B 10-4log5
  3. C 9+4log5
  4. D 9-4log5
Verified Solution

Answer & Solution

Correct Answer

(C) 9+4log5

Step-by-step Solution

Detailed explanation

Given: fx=∫2x3-3x2+4x-5x2dx ⇒fx=∫2x-3+4x-5x2dx ⇒fx=x2-3x+4logx+5x+C where, C is the constant of integartion. f1=1 ⇒1-3+4×0+5+C=1 ⇒C=-2 So, fx=x2-3x+4logx+5x-2 ⇒f5=25-15+4log5+1-2 ⇒f5=9+4log5