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TS EAMCET · Maths · Straight Lines

In a ABC, 2x+3y+1=0, x+2y-12=0 are the perpendicular bisectors of its sides AB and AC respectively and if A is (3, 2), then the slope of the side BC is

  1. A 1
  2. B 13
  3. C 53
  4. D 52
Verified Solution

Answer & Solution

Correct Answer

(C) 53

Step-by-step Solution

Detailed explanation

mAB=-1-23=32 AB≡y-2=32x-3 ⇒2y-4=3x-9 ⇒3x-2y-5=0 mAC=-1-12=2 AC≡y-2=2x-3 ⇒2x-y-4=0 For point E, solving 2x+3y+1=0 & 3x-2y-5=0 ⇒6x+9y+3=0, 6x-4y-10=0 Subtracting these two we get y=-1 Now put y=-1 in 2x+3y+1=0 we get x=1 E≡1,-1 Let B(p,q),…
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