TS EAMCET · Maths · Straight Lines
If the origin is shifted to the point \(\left(\frac{3}{2},-2\right)\) by the translation of axes, then the transformed equation of \(2 x^2+4 x y+y^2+2 x-2 y+1=0\) is
- A \(4 x^2+8 x y+2 y^2-16=0\)
- B \(2 x^2-8 x y+y^2=0\)
- C \(4 x^2+8 x y+2 y^2+9=0\)
- D \(2 x^2-4 x y+y^2+16=0\)
Answer & Solution
Correct Answer
(C) \(4 x^2+8 x y+2 y^2+9=0\)
Step-by-step Solution
Detailed explanation
Put \(x=x^{\prime}+\frac{3}{2}\) and \(y=y^t-2\), we get…
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