TS EAMCET · Maths · Quadratic Equation
If the minimum value of the quadratic expression \(x^2+5 x-2\) is \(M\) and it exists at \(a\), then \(\frac{M}{a}\) is equal to
- A 3.3
- B \(\frac{33}{5}\)
- C 2.5
- D −0.25
Answer & Solution
Correct Answer
(A) 3.3
Step-by-step Solution
Detailed explanation
Given, minimum value of \(x^2+5 x-2\) is \(M\) and it exists at \(a\). So, \(\begin{aligned} & \text { So, } & a & =\frac{-5}{2} \\ & \therefore & M & =\left(\frac{-5}{2}\right)^2+5\left(\frac{-5}{2}\right)-2 \end{aligned}\)…
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Maths
- The area bounded by \(y=x^2+2, x\)-axis, \(x=1\) and \(x=2\) isTS EAMCET 2004 Medium
- The shortest distance between the lines \(\mathbf{r}=3 \mathbf{i}+5 \mathbf{j}+7 \mathbf{k}+\lambda(\mathbf{i}+2 \mathbf{j}+\mathbf{k}) \quad\) and \(\mathbf{r}=-\mathbf{i}-\mathbf{j}-\mathbf{k}+\mu(7 \mathbf{i}-6 \mathbf{j}+\mathbf{k})\) isTS EAMCET 2013 Medium
- The image of the line \(x+y-2=0\) in the \(y\)-axis isTS EAMCET 2010 Easy
- \(\left(x^4+1\right)=\frac{1}{a}(x+1)^4\) is a reciprocal equationTS EAMCET 2022 Medium
- With respect to the roots of the equation \(3 x^3+b x^2+b x+3=0\), match the items of List-I with those of List-II.
TS EAMCET 2024 Easy - If \(a=3, b=5, c=7\) are the sides of a triangle ABC, then \(\cot \mathrm{A}+\cot \mathrm{B}+\cot \mathrm{C}=\)TS EAMCET 2025 Medium
More PYQs from TS EAMCET
- Which one of the following is a secondary alcohol?TS EAMCET 2004 Easy
- At time \(t=0\), a particle leaves the origin and moves in the positive direction of the \(X\)-axis. If the velocity of the particles varies as \(\mathbf{v}(t)=\mathbf{v}_0\left(1-\frac{t}{t_0}\right),\left|\mathbf{v}_0\right|=10 \mathrm{~m} / \mathrm{s}\) and \(t_0=10 \mathrm{~s}\), then the distance covered by the particle during the first \(20 \mathrm{~s}\) isTS EAMCET 2021 Hard
- If \(\alpha, \beta, \gamma\), are the roots of the equation \(x^3+4 x+1=0\), then \((\alpha+\beta)^{-1}+(\beta+\gamma)^{-1}+(\gamma+\alpha)^{-1}\) is equal toTS EAMCET 2003 Hard
- Let \(\alpha\) be a common root of the equations \(x^3-2 x-25 \lambda=0\), \(3 x^3-8 x-\frac{175}{3} \lambda=0\) and \(\lambda>0\). Then \(\lambda=\)TS EAMCET 2022 Medium
- \(A\) and \(B\) are two non square matrices. If \(P=A+B, Q=A^T B, R=A B^T\), then the matrices whose order is equal to the order of A areTS EAMCET 2025 Medium
- The distance between the parallel lines given by \((x+7 y)^2+4 \sqrt{2}(x+7 y)-42=0\) isTS EAMCET 2012 Medium