TS EAMCET · Maths · Straight Lines
If \(A=(-1,2)\) and \(B=(1,-2)\) are two points and \(P\) is a variable point such that the area of \(\triangle P A B\) is always one, then the equation of the locus of \(P\) is
- A \(4 x^2+4 x y+y^2=1\)
- B \(x^2+10 x y+25 y^2-34 x-170 y=0\)
- C \(x^2-6 x y+9 y^2+22 x-66 y-23=0\)
- D \(16 x^2-24 x y+9 y^2-62 x+34 y+46=0\)
Answer & Solution
Correct Answer
(A) \(4 x^2+4 x y+y^2=1\)
Step-by-step Solution
Detailed explanation
Let \(P\) be \((x, y)\). We have, ar \((\triangle P A B)=1\)…
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