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TS EAMCET · Maths · Quadratic Equation

Let \(E_1 \equiv a x^2+b x+c, E_2 \equiv b x^2+c x+a\), \(E_3 \equiv c x^2+b x+a\) and \(\frac{a^2}{b c}+\frac{b^2}{c a}+\frac{c^2}{a b}=3\). If these quadratic expressions have a common zero, then the quadratic expression having zeroes that are common to \(E_2\) and \(E_3\) and different from the zeroes of \(E_1\) is

  1. A \(x^2-\frac{a(b+c)}{b c} x+b c\)
  2. B \(a x^2+b x+c\)
  3. C \(x^2-b(c+a) x+a c\)
  4. D \(x^2-\frac{a(b+c) x}{b c}+\frac{a^2}{b c}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(x^2-\frac{a(b+c) x}{b c}+\frac{a^2}{b c}\)

Step-by-step Solution

Detailed explanation

We have \[ \begin{aligned} & E_1=a x^2+b x+c, \quad E_2=b x^2+c x+a \\ & E_3=c x^2+b x+a \text { and } \frac{a^2}{b c}+\frac{b^2}{c a}+\frac{c^2}{a b}=3 \end{aligned} \] \(E_1, E_2\) and \(E_3\) have 1,3 common roots and…