TS EAMCET · Maths · Pair of Lines
If \((2,-1)\) is the point of intersection of the pair of lines \(2 x^2+a x y+3 y^2+b x+c y-3=0\) then \(3 a+2 b+c=\)
- A 11
- B 0
- C 1
- D 21
Answer & Solution
Correct Answer
(A) 11
Step-by-step Solution
Detailed explanation
\(2 x^2+a x y+3 y^2+b x+c y-3=0\)....(i) Differentiate partialliy w.r.t. \(x\) and \(y\) \(\begin{aligned} & 4 x+a y+b=0...(ii) \\ & 6 y+a y+c=0...(iii) \end{aligned}\) Point (\(2,-1\)) satisfies (i), (ii) and (iii) \(\Rightarrow 8-2 a+3+2 b-c-3=0\)…
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