TS EAMCET · Maths · Straight Lines
The ends of a rod of length \(l\) moves on two mutually perpendicular lines. The locus of the point on the rod which divides it in the ratio \(1: 2\) is
- A \(3 x^2+4 y^2=2 f^2\)
- B \(9 x^2+16 y^2=5 l^2\)
- C \(4 x^2+3 y^2=6^2\)
- D \(9 x^2+36 y^2=4 i^2\)
Answer & Solution
Correct Answer
(D) \(9 x^2+36 y^2=4 i^2\)
Step-by-step Solution
Detailed explanation
Let mutually perpendicular lines are axes only. \(\because \quad \frac{2 a}{3}=h \Rightarrow a=\frac{3 h}{2}\) and \(\frac{b}{3}=k\)…
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