TS EAMCET · Maths · Quadratic Equation

Let \(\alpha\) and \(\beta\) be the roots of the quadratic equation \(a x^2+b x+c=0\). Observe the lists given below
The correct match of List-I from List-II is (i) (ii) (iii) (iv)

A \(\begin{array}{llll}\mathrm{E} & \mathrm{B} & \mathrm{D} & \mathrm{F}\end{array}\)
B \(\begin{array}{llll}\mathrm{E} & \mathrm{B} & \mathrm{A} & \mathrm{D}\end{array}\)
C \(\begin{array}{llll}\mathrm{E} & \mathrm{D} & \mathrm{B} & \mathrm{F}\end{array}\)
D \(\begin{array}{llll}\mathrm{E} & \mathrm{B} & \mathrm{D} & \mathrm{A}\end{array}\)

Verified Solution

Answer & Solution

Correct Answer

(D) \(\begin{array}{llll}\mathrm{E} & \mathrm{B} & \mathrm{D} & \mathrm{A}\end{array}\)

Step-by-step Solution

Detailed explanation

Using the condition that the roots of \(a x^2+b x+c=0\) may be in the ratio \(m: n\) is \(m n b^2=a c(m+n)^2\). (i) If the roots are \(\alpha=\beta\), then \[ \begin{aligned} \alpha \cdot \alpha b^2 & =a c(\alpha+\alpha)^2 \\ \Rightarrow \quad b^2 & =4 a c \end{aligned} \]…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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Let \(\alpha\) and \(\beta\) be the roots of the quadratic equation \(a x^2+b x+c=0\). Observe the lists given below The correct match of List-I from List-II is (i) (ii) (iii) (iv)

Step-by-step Solution

Let \(\alpha\) and \(\beta\) be the roots of the quadratic equation \(a x^2+b x+c=0\). Observe the lists given below
The correct match of List-I from List-II is (i) (ii) (iii) (iv)