TS EAMCET · Maths · Complex Number
\(\left(\frac{\cos \theta+i \sin \theta}{\sin \theta+i \cos \theta}\right)^8+\left(\frac{1+\cos \theta-i \sin \theta}{1+\cos \theta+i \sin \theta}\right)^{16}=\)
- A \(2 \cos 8 \theta\)
- B \(2 \cos 16 \theta\)
- C \(2 \sin 8 \theta\)
- D \(2 \sin 16 \theta\)
Answer & Solution
Correct Answer
(B) \(2 \cos 16 \theta\)
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