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TS EAMCET · Physics · Laws of Motion

A bullet of mass \(m\) enters a wooden block of length \(L\) at a speed \(v_1\) and emerges out of block with a speed \(v_2\). If \(F\) is the average force which impeded its motion through the wooden block, then (Assume uniform deceleration inside the block)

  1. A \(F=\frac{m}{2 L}\left(v_2^2-v_1^2\right)\)
  2. B \(F=\frac{m}{4 L}\left(v_2^2+v_1^2\right)\)
  3. C \(F=2 \frac{m}{L}\left(v_2-v_1\right)^2\)
  4. D \(F=\frac{m}{2 L}\left(v_2+v_1\right)^2\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(F=\frac{m}{2 L}\left(v_2^2-v_1^2\right)\)

Step-by-step Solution

Detailed explanation

Given that, mass of bullet \(=m\) Average resistance force \(=F\) i.e. retardation, \(a=F / m\) Using equation of kinematics,…
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