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TS EAMCET · Maths · Trigonometric Ratios & Identities

Let \(a\) be maximum value of \((3 \cos \theta-4 \sin \theta)\) and \(\theta \neq \frac{n \pi}{2}\). If \(\alpha=a \sin ^2 \theta\). \(\cos ^3 \theta\) and \(\beta=a \sin ^3 \theta \cdot \cos ^2 \theta\), then \(\sqrt{\frac{\left(\alpha^2+\beta^2\right)^5}{(\alpha \beta)^4}}=\)

  1. A \(5 \sin \frac{\theta}{2} \cos ^2 \frac{\theta}{2}\)
  2. B \(-3 \sin \theta\)
  3. C 5
  4. D 16
Verified Solution

Answer & Solution

Correct Answer

(C) 5

Step-by-step Solution

Detailed explanation

Maximum value of \(3 \cos \theta-4 \sin \theta\) \(a=\sqrt{3^2+(-4)^2}=5\) \(\therefore \quad \alpha=5 \sin ^2 \theta \cos ^3 \theta\) \(\beta=5 \sin ^3 \theta \cos ^2 \theta\) Now, \(\alpha^2+\beta^2=5^2\left(\sin ^4 \theta \cos ^6 \theta+\sin ^6 \theta \cos ^4 \theta\right)\)…