TS EAMCET · Maths · Trigonometric Ratios & Identities
Let \(a\) be maximum value of \((3 \cos \theta-4 \sin \theta)\) and \(\theta \neq \frac{n \pi}{2}\). If \(\alpha=a \sin ^2 \theta\). \(\cos ^3 \theta\) and \(\beta=a \sin ^3 \theta \cdot \cos ^2 \theta\), then \(\sqrt{\frac{\left(\alpha^2+\beta^2\right)^5}{(\alpha \beta)^4}}=\)
- A \(5 \sin \frac{\theta}{2} \cos ^2 \frac{\theta}{2}\)
- B \(-3 \sin \theta\)
- C 5
- D 16
Answer & Solution
Correct Answer
(C) 5
Step-by-step Solution
Detailed explanation
Maximum value of \(3 \cos \theta-4 \sin \theta\) \(a=\sqrt{3^2+(-4)^2}=5\) \(\therefore \quad \alpha=5 \sin ^2 \theta \cos ^3 \theta\) \(\beta=5 \sin ^3 \theta \cos ^2 \theta\) Now, \(\alpha^2+\beta^2=5^2\left(\sin ^4 \theta \cos ^6 \theta+\sin ^6 \theta \cos ^4 \theta\right)\)…
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