TS EAMCET · Maths · Vector Algebra
\(\vec{b}\) and \(\vec{c}\) are non collinear vectors and \((\vec{c} \cdot \vec{c}) \vec{a}=\vec{c}\). If \((\vec{a} \cdot \vec{c}) \vec{b}-(\vec{a} \cdot \vec{b}) \vec{c}+(\vec{a} \cdot \vec{b}) \vec{b}=(4-2 \beta-\sin \alpha) \vec{b}+\left(\beta^2-1\right) \vec{c}\) then \(\sin (\alpha+\beta)=\)
- A \(0\)
- B \(1\)
- C \(\sin 1\)
- D \(\cos 1\)
Answer & Solution
Correct Answer
(D) \(\cos 1\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text{c}=|\overrightarrow{\mathrm{c}}|^2 \overrightarrow{\mathrm{a}} \\ & \Rightarrow \vec{c} \cdot \vec{c}=|\overrightarrow{\mathrm{c}}|^2 \cdot \overrightarrow{\mathrm{a}} \cdot \vec{c} \\ & \Rightarrow|\vec{c}|^2(\overrightarrow{\mathrm{a}} \cdot…
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