TS EAMCET · Maths · Permutation Combination
A student has to answer a multiple-choice question having 5 alternatives in which two or more than two alternatives are correct. Then the number of ways in which the student can answer that question is
- A \(31\)
- B \(30\)
- C \(27\)
- D \(26\)
Answer & Solution
Correct Answer
(D) \(26\)
Step-by-step Solution
Detailed explanation
Total ways to select alternatives = \(2^5 = 32\) Ways to select 0 or 1 alternative = \(C(5,0) + C(5,1) = 1 + 5 = 6\) Ways to select two or more alternatives = \(32 - 6 = 26\)
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